Please give your description of an aggregate average and how you figure it. I have my thoughts, but want to see others.   For this purpose, aggregate  average encompasses 2 goes. Thanks!

Average is total time on multiple runs, can also apply to a long go and a short go. The only time it wouldn't be an average is if the short go was a clean slate finals.

Sometimes you will find a producer who does an actual "average" - divide the aggregate by the number of runs, but for the most part, in the rodeo world, the "Average" has usually been an aggregate of all runs. I think that is why some announcers now use the term aggregate more often to avoid the confusion in spectators that are not familiar with the slang used. 

I've never taken the time to see if the aggregate results come out the same as if you averaged them.

The problem with agregate average is with the splits. I went to a weekend barrel race and the average was on half second splits. Just like one run. The girl that won the 2D buckle ran 1D times both runs. The 5D winner was somewhere in the 3D. It isn't a true average because you don't divide at all. You add the times together and do not divide. You also add the amount time in your splits like you you have two runs with half second splits so it's .5 + .5.= 1 second splits for the average. At rodeos it is much easier because you don't have various divisions like a 4D. You have ropers rope, barrel racers run, bronc riders ride and no divisions. Just add up times or scores and you are done.

I know of one producer that figures the 2D, 3D, etc. on the fastest 1D times for each day. The fastest aggregate for one person does win the 1D, but the other divisions are based on the fast times of each day. For example, Runner 1 runs a 17.1 on Friday to win it, Runner 2 runs a 17.0 on Saturday to win it and Runner 3 runs a 17.2 on Sunday to win it. The other D's are based on those 3 times put together, but the one out of the three with the fastest aggregate would win the 1D. This avoids those odd splits as mentioned above so runners place in the average in the D's they ran in. Hopefully that makes sense. I actually like it this way. 

Average would be based on 1 horse/rider combinations 2 runs combined. Splits are regular x2. So if half a second in one round, the split would be a full second for a two run average.

Aggregate (*to me*) could be more of a point based system. For example 10 holes. 1st is 10 pts, 2nd is 9 and so on. 

Horse/Rider 1 - Day 1 17.0 , 1st 1D    Day 2 17.3, 5th 1D = 16pts on combined time of 34.3

Horse/Rider 2 - Day 1 17.2, 2nd 1D   Day 2 17.2, 2nd 1D = 18pts on combined time of 34.4

On a points basis; Rider 2 would win. 

On a combined time basis; Rider 1 would win

The most important thing is the producer states HOW they will be calculating prior to the event. I have also seen for the average taking the two fastest times regardless of horse/rider combination. 

this was what I was wanting someone to point out.  That on an aggregate of a 2 day run, to get the splits correct for 2D, 3D, 4D, 5D, you have to double the split interval.  If it was a 3 day run you would triple the split interval.  I was at an event this weekend and I was questioning their aggregate results.  When I spoke to office staff to bring to their attention, it was obvious they didn't know what I was saying.  I specifically asked about doubling the splits for the final aggregate results.  Answer was, no, it is just regular .5, 1.0, etc, etc splits.   Well, when it was all said and done, their aggregate average was figured correctly.  They use saddlebook.com, so not sure if it's automatically figured within saddlebook's set-up, or the producer had to set it up.